Integrand size = 41, antiderivative size = 96 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=-\frac {(A+3 i B) c^2 x}{a}-\frac {(i A-3 B) c^2 \log (\cos (e+f x))}{a f}-\frac {2 (A+i B) c^2}{a f (i-\tan (e+f x))}+\frac {i B c^2 \tan (e+f x)}{a f} \]
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Time = 0.18 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {3669, 78} \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=-\frac {2 c^2 (A+i B)}{a f (-\tan (e+f x)+i)}-\frac {c^2 (-3 B+i A) \log (\cos (e+f x))}{a f}-\frac {c^2 x (A+3 i B)}{a}+\frac {i B c^2 \tan (e+f x)}{a f} \]
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Rule 78
Rule 3669
Rubi steps \begin{align*} \text {integral}& = \frac {(a c) \text {Subst}\left (\int \frac {(A+B x) (c-i c x)}{(a+i a x)^2} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {(a c) \text {Subst}\left (\int \left (\frac {i B c}{a^2}-\frac {2 (A+i B) c}{a^2 (-i+x)^2}+\frac {i (A+3 i B) c}{a^2 (-i+x)}\right ) \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {(A+3 i B) c^2 x}{a}-\frac {(i A-3 B) c^2 \log (\cos (e+f x))}{a f}-\frac {2 (A+i B) c^2}{a f (i-\tan (e+f x))}+\frac {i B c^2 \tan (e+f x)}{a f} \\ \end{align*}
Time = 4.42 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.86 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=\frac {\frac {B (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)}+\frac {(i A-3 B) c^2 \left (\log (i-\tan (e+f x))-\frac {2 i}{-i+\tan (e+f x)}\right )}{a}}{f} \]
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Time = 0.16 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.60
method | result | size |
derivativedivides | \(\frac {i B \,c^{2} \tan \left (f x +e \right )}{a f}+\frac {2 i c^{2} B}{f a \left (-i+\tan \left (f x +e \right )\right )}+\frac {2 c^{2} A}{f a \left (-i+\tan \left (f x +e \right )\right )}+\frac {i c^{2} A \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f a}-\frac {3 c^{2} B \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f a}-\frac {c^{2} A \arctan \left (\tan \left (f x +e \right )\right )}{f a}-\frac {3 i c^{2} B \arctan \left (\tan \left (f x +e \right )\right )}{f a}\) | \(154\) |
default | \(\frac {i B \,c^{2} \tan \left (f x +e \right )}{a f}+\frac {2 i c^{2} B}{f a \left (-i+\tan \left (f x +e \right )\right )}+\frac {2 c^{2} A}{f a \left (-i+\tan \left (f x +e \right )\right )}+\frac {i c^{2} A \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f a}-\frac {3 c^{2} B \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 f a}-\frac {c^{2} A \arctan \left (\tan \left (f x +e \right )\right )}{f a}-\frac {3 i c^{2} B \arctan \left (\tan \left (f x +e \right )\right )}{f a}\) | \(154\) |
norman | \(\frac {\frac {\left (3 i c^{2} B +2 c^{2} A \right ) \tan \left (f x +e \right )}{a f}+\frac {i c^{2} B \tan \left (f x +e \right )^{3}}{a f}-\frac {\left (3 i c^{2} B +c^{2} A \right ) x}{a}-\frac {-2 i A \,c^{2}+2 c^{2} B}{a f}-\frac {\left (3 i c^{2} B +c^{2} A \right ) x \tan \left (f x +e \right )^{2}}{a}}{1+\tan \left (f x +e \right )^{2}}-\frac {\left (-i A \,c^{2}+3 c^{2} B \right ) \ln \left (1+\tan \left (f x +e \right )^{2}\right )}{2 a f}\) | \(165\) |
risch | \(-\frac {c^{2} {\mathrm e}^{-2 i \left (f x +e \right )} B}{a f}+\frac {i c^{2} {\mathrm e}^{-2 i \left (f x +e \right )} A}{a f}-\frac {6 i c^{2} B x}{a}-\frac {2 c^{2} A x}{a}-\frac {6 i c^{2} B e}{a f}-\frac {2 c^{2} A e}{a f}-\frac {2 c^{2} B}{f a \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )}+\frac {3 c^{2} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) B}{a f}-\frac {i c^{2} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right ) A}{a f}\) | \(167\) |
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Time = 0.27 (sec) , antiderivative size = 153, normalized size of antiderivative = 1.59 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=-\frac {2 \, {\left (A + 3 i \, B\right )} c^{2} f x e^{\left (4 i \, f x + 4 i \, e\right )} - {\left (i \, A - B\right )} c^{2} + {\left (2 \, {\left (A + 3 i \, B\right )} c^{2} f x - {\left (i \, A - 3 \, B\right )} c^{2}\right )} e^{\left (2 i \, f x + 2 i \, e\right )} - {\left ({\left (-i \, A + 3 \, B\right )} c^{2} e^{\left (4 i \, f x + 4 i \, e\right )} + {\left (-i \, A + 3 \, B\right )} c^{2} e^{\left (2 i \, f x + 2 i \, e\right )}\right )} \log \left (e^{\left (2 i \, f x + 2 i \, e\right )} + 1\right )}{a f e^{\left (4 i \, f x + 4 i \, e\right )} + a f e^{\left (2 i \, f x + 2 i \, e\right )}} \]
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Time = 0.37 (sec) , antiderivative size = 194, normalized size of antiderivative = 2.02 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=- \frac {2 B c^{2}}{a f e^{2 i e} e^{2 i f x} + a f} + \begin {cases} \frac {\left (i A c^{2} - B c^{2}\right ) e^{- 2 i e} e^{- 2 i f x}}{a f} & \text {for}\: a f e^{2 i e} \neq 0 \\x \left (- \frac {- 2 A c^{2} - 6 i B c^{2}}{a} + \frac {\left (- 2 A c^{2} e^{2 i e} + 2 A c^{2} - 6 i B c^{2} e^{2 i e} + 2 i B c^{2}\right ) e^{- 2 i e}}{a}\right ) & \text {otherwise} \end {cases} - \frac {i c^{2} \left (A + 3 i B\right ) \log {\left (e^{2 i f x} + e^{- 2 i e} \right )}}{a f} + \frac {x \left (- 2 A c^{2} - 6 i B c^{2}\right )}{a} \]
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Exception generated. \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=\text {Exception raised: RuntimeError} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 271 vs. \(2 (84) = 168\).
Time = 0.51 (sec) , antiderivative size = 271, normalized size of antiderivative = 2.82 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=\frac {\frac {{\left (-i \, A c^{2} + 3 \, B c^{2}\right )} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}{a} + \frac {2 \, {\left (i \, A c^{2} - 3 \, B c^{2}\right )} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - i\right )}{a} - \frac {{\left (i \, A c^{2} - 3 \, B c^{2}\right )} \log \left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1\right )}{a} - \frac {-i \, A c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 3 \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 2 i \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + i \, A c^{2} - 3 \, B c^{2}}{{\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 1\right )} a} - \frac {3 i \, A c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 9 \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 10 \, A c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 22 i \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 3 i \, A c^{2} + 9 \, B c^{2}}{a {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - i\right )}^{2}}}{f} \]
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Time = 8.81 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.15 \[ \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^2}{a+i a \tan (e+f x)} \, dx=\frac {\ln \left (\mathrm {tan}\left (e+f\,x\right )-\mathrm {i}\right )\,\left (-\frac {3\,B\,c^2}{a}+\frac {A\,c^2\,1{}\mathrm {i}}{a}\right )}{f}+\frac {\frac {\left (A\,c^2-B\,c^2\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{a}+\frac {\left (A\,c^2+B\,c^2\,3{}\mathrm {i}\right )\,1{}\mathrm {i}}{a}}{f\,\left (1+\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}+\frac {B\,c^2\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}{a\,f} \]
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